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Portalesman
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Joined:  Sun Oct 14th, 2007 
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YOUR AGE BY DINER & RESTAURANT MATH
>>
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>> This is pretty neat.
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>> DON'T CHEAT BY SCROLLING DOWN FIRST!
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>> It takes less than a minute. Work this out as you read ...
>> Be sure you don't read the bottom until you've worked it out!
>> This is not one of those waste of time things, it's fun.
>>
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>> 1. First of all, pick the number of times a week that you
> would like to go out to eat. (more than once but less than 10)
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>> 2. Multiply this number by 2 (just to be bold)
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>> 3. Add 5
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>> 4. Multiply it by 50
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>> 5. If you have already had your birthday this year add 1757...
>> If you haven't, add 1756.
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>> 6. Now subtract the four digit year that you were born.
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>> You should have a three digit number.
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>> The first digit of this was your original number. (I.e., How
> many times you want to go out to restaurants in a week.)
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>> The next two numbers are
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>> YOUR AGE !  (Oh YES, it is!!!)
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>> THIS IS THE ONLY YEAR (2007) IT WILL EVER WORK, SO SPREAD IT
>>AROUND WHILE IT LASTS
>
> 

Kid_Naitch
Joined:  Tue Oct 30th, 2007 
Location:  IOWA 
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Worked for me (five times/week; 25 yrs old). Who the hell has time to figure that shit out?

srossi
Joined:  Sun Oct 14th, 2007 
Location:  New York USA 
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It does work if I pick 1 time (the minimum allowed). Unless it's a special occassion or I'm taking my girlfriend out, I absolutely never eat out though.

kargol

Well, of course it works, it's basic maths.
Work out the equation, multiply it out, and you get:
(2x + 5) x 50, which is 100x + 250, then you add 1757 (or 1756) and take off your age, which gives you:
100x + 2007 (or 2006)  y
where x is the number of times you eat out and y is the year of your birth.
Given x must be between 1 and 9, 100x will be between 100 and 900.
Given 2007  y is how old you are, this answer will be, er, how old you are.

CanadianHorseman

kargol wrote: Well, of course it works, it's basic maths.
Work out the equation, multiply it out, and you get:
(2x + 5) x 50, which is 100x + 250, then you add 1757 (or 1756) and take off your age, which gives you:
100x + 2007 (or 2006)  y
where x is the number of times you eat out and y is the year of your birth.
Given x must be between 1 and 9, 100x will be between 100 and 900.
Given 2007  y is how old you are, this answer will be, er, how old you are.
You are a LIAR !!!!!!!!!! It is magic DAMMIT !!!!!!!!!!!!!!:P

kargol

Won't work for centenerians, btw.

beejmi
THE BIG KAHUNA
Joined:  Sat Oct 13th, 2007 
Location:  Philly 
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It's MAGIC. *AWESOME*

gwlee7
Hall Of Famer

CanadianHorseman wrote: kargol wrote: Well, of course it works, it's basic maths.
Work out the equation, multiply it out, and you get:
(2x + 5) x 50, which is 100x + 250, then you add 1757 (or 1756) and take off your age, which gives you:
100x + 2007 (or 2006)  y
where x is the number of times you eat out and y is the year of your birth.
Given x must be between 1 and 9, 100x will be between 100 and 900.
Given 2007  y is how old you are, this answer will be, er, how old you are.
You are a LIAR !!!!!!!!!! It is magic DAMMIT !!!!!!!!!!!!!!:P
kargol = the black scorpion

srossi
Joined:  Sun Oct 14th, 2007 
Location:  New York USA 
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Won't work for centenerians, btw.
That's OK, I eat meat.

beejmi
THE BIG KAHUNA
Joined:  Sat Oct 13th, 2007 
Location:  Philly 
Posts:  43389 
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You moron, the centenerians were the Roman guards from back in Biblical times.

gwlee7
Hall Of Famer

And here all this time I thought centenerians were those worm like things with 100 legs.

The Ultimate Sin
Hall Of Famer

srossi wrote: It does work if I pick 1 time (the minimum allowed). Unless it's a special occassion or I'm taking my girlfriend out, I absolutely never eat out though.
Do you mean you won't go down on her ever, or just not after a restaurant meal?

srossi
Joined:  Sun Oct 14th, 2007 
Location:  New York USA 
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I typically go down on her at the restaurant.
